```
import numpy as np
import os
import re
seoul_file = open("seoul.txt", "r", encoding = "utf8")
seoul = seoul_file.read().splitlines()
print ("Seoul Data Received"
seoul_file.close()
time12_seoul = []
date12_s = []
date12_s2 = []
def clean_text(inputString): #Remove special characters
text_rmv = re.sub('[-=+,#/:^[email protected]*\"※~ ·!NNone'|}\(\)\[\]`\'…》\”\“\’·]', '', str(inputString))
return text_rmv
def list_chunk(lst,n): #Splitlist(when dividing by date)
return [lst[i:i+n] for i in range(0, len(lst), n)]
def None_del(n,lst):
lst.clear()
for a in n:
a = list(filter(None, a))
lst.append(a)
return lst
for s_time in seoul:
#Only 12 o'clock data in Seoul is contained
if '12:00' in s_time:
time12_seoul.append(s_time)
for s_data12 in time12_seoul:
list_s = s_data12.split(',')
del list_s[0]
del list_s[1]
Value_seoul12 = list_s[0].split(":")
del Value_seoul12[0]
Value_seoul12 = clean_text(Value_seoul12)
if Value_seoul12 == '':
date12_s.append(Value_seoul12)
continue
else:
Value_seoul12 = (Value_seoul12)
date12_s.append(Value_seoul12)
#print(Value_seoul12)
Value2_seoul12 = list_s[1].split(":")
del Value2_seoul12[0]
Value2_seoul12 = clean_text(Value2_seoul12)
if Value2_seoul12 == '':
date12_s2.append(Value2_seoul12)
continue
else:
Value2_seoul12 = (Value2_seoul12)
date12_s2.append(Value2_seoul12)
#print(Value2_seoul12)
s_12 = list_chunk(date12_s, 40)
s2_12 = list_chunk(date12_s2, 40)
date12_s = None_del(s_12, date12_s)
date12_s2 = None_del(s2_12, date12_s2)
```

I coded in this way and received the data I wanted from the file, but ```
int(
Date12_s)
```

is tied up and the sum of the numbers in the list is calculated using `sum`

, and even if you make the ` int`

type with `map`

, the sum is not found, so I'm asking you a question.

What I have to do now is to find the sum of `date12_s`

and `date12_s2`

respectively, but I don't know where to start, so ask me!

2022-09-20 14:24

2022-09-20 14:24

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